A jogger completes one round of a circular track of diameter 210m in 2 minutes find the distance covered and the displacement at the end of 5 minutes
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210m
Explanation:
given, jogger completes one round of a circular track of diameter 210m in 2 minutes
=> he covers the circumference in 2mins
=> he covers π×210m in 2×60s
=> he covers ²²/₇×210m in 120s
=> his speed is 22×30÷120 m/s = 5.5 m/s
At the end of 5mins = 300s, he will thus cover 300×5.5m = 1650m
circumference = ²²/₇×210m = 660m
=> he covers the circular track 1650/660 times = 165/66 = 2.5 times
since after each complete round, the jogger will return to the point from where he started, that means after 2 rounds his displacement will be 0. In 0.5 round, he will be opposite to the starting point, which implies that his displacement will be equal to the diameter of the track after 5mins.
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