A jogger desires to run a certain course in 1/4 less time than she usually takes, by what percent must she increase her average running speed to accomplish this goal?
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Formula used: Distance = Time*Speed
Let the speed at which she travels be x and the time she takes be t
If the time the jogger takes to complete the course is 1/4 less than she usually takes,
34t∗A=xt34t∗A=xt -> A=43∗X=(1+13)XA=43∗X=(1+13)X
Therefore, the percentage by which the jogger must increase her running speed is 13∗100=3313
Let the speed at which she travels be x and the time she takes be t
If the time the jogger takes to complete the course is 1/4 less than she usually takes,
34t∗A=xt34t∗A=xt -> A=43∗X=(1+13)XA=43∗X=(1+13)X
Therefore, the percentage by which the jogger must increase her running speed is 13∗100=3313
saeed14ghasura:
plz give answer in percentage
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