Question

a jogger jogs along one length and breadth of a rectangular park.If the dimensions of park are 150m×120m,then find the distance travelled and displacement of the jogger.

Answer 1

the distance travelled = perimeter of the path
= 2(150+ 120)
=2 x 270
=540m

the displacement = 0

because the jogger returns to the starting point so there is no shortest point between initial and final point

Answer 2

Distance travelled by the jogger = Perimeter of the rectangular park.

Given dimensions = 150m×120m.

Perimeter = 2(l+b) = 2 ( 150 + 120 ) = 2(270) = 540m.

Displacement is 0. As he starts from a point and reaches the same point.

So Displacement = 0.

:)