a jogger jogs along one length and breadth of a rectangular park.If the dimensions of park are 150m×120m,then find the distance travelled and displacement of the jogger.
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Answered by
76
the distance travelled = perimeter of the path
= 2(150+ 120)
=2 x 270
=540m
the displacement = 0
because the jogger returns to the starting point so there is no shortest point between initial and final point
= 2(150+ 120)
=2 x 270
=540m
the displacement = 0
because the jogger returns to the starting point so there is no shortest point between initial and final point
Answered by
52
Distance travelled by the jogger = Perimeter of the rectangular park.
Given dimensions = 150m×120m.
Perimeter = 2(l+b) = 2 ( 150 + 120 ) = 2(270) = 540m.
Displacement is 0. As he starts from a point and reaches the same point.
So Displacement = 0.
:)
Given dimensions = 150m×120m.
Perimeter = 2(l+b) = 2 ( 150 + 120 ) = 2(270) = 540m.
Displacement is 0. As he starts from a point and reaches the same point.
So Displacement = 0.
:)
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