Question

A Jogger jogs along one length and breadth of a rectangular park.If the dimensions of the park are 150m120m,then find the distance travelled and the displacement of the Jogger.Spam answers will be reported.

Answer 1

Answer:

Distance travelled = 270 m

Displacement = 30$\sqrt{40}$

Explanation:

The distance covered by the jogger is one breadth and one length of the rectangular park. The measurements given are:

Length = 150 m

Breadth = 120 m

So, total distance covered is 270 m.

We also know that the displacement is the shortest distance between the start and end point. So, we get a diagonal is shown in the attached picture.

As this forms a right angled triangle where we know the altitude and base, we have to find the hypotenuse which is the displacement.

So,

$Altitude^{2} + Base^{2} = Hypotenuse^{2}$

$120^{2} + 150^{2} = Hypotenuse^{2}$

36900 = $Hypotenuse^{2}$

Therefore hypotense = $\sqrt{36900}$

= $30\sqrt{40}$

How to find the root of 36900

• First we will find all factors under the square root: 36900 has the square factor of 900.

• Let's check this width √900*41=√36900.

• As you can see the radicals are not in their simplest form.

• Now extract and take out the square root √900 * √41.

• Root of √900=30 which results into 30√41