Question

A jogger jokes along 1 length and breadth of a rectangular Park if the dimensions of Park are 150 m into 120 M then find the distance travelled and displacement of the Joker

Answer 1

Heya........


the distance travelled
= perimeter of the path
= 2(150+ 120)=2 x 270
=540m

the displacement = 0

because the jogger returns to the starting point so there is no shortest point between initial and final point

tysm.....@Gozmit

Answer 2

Hey mate!

Here's your answer!!

➡ The distance travelled,

= Perimeter of the path

= 2(150 + 120)

= 2(270)

= 540m

➡ The displacement = 0

This is because the jogger reaches the same position from where he started, so there's no shortest distance between initial and final point.

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