A joker's cap in the form of a cone of radius 7cm and h=24cm find the area of the sheet required to make 10 such caps
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R=7cm
h=24
l=?
l=√r^2+h^2
l=√7^2+24^2
l=√625
l=25cm
C. S. A of cone=22/7*r*h
=22/7*7*25
=550cm^2
Area of sheet required to make 10 such caps =C. S. A*10caps
=550*10cm^2
5500cm^2
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