A joker's cap is in shape of right circular cone h- 24 cm and r- 7 cm .find the area of the sheet required for 10 cap
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CSA of cone=pi×r×l
CSA of 10 cap=10×pi×r×l
Solve by yourself
CSA of 10 cap=10×pi×r×l
Solve by yourself
Answered by
2
given:height =24cm
radius=7cm
therefore slant height( l ) =√h^2+r^2
= √576+49 ( square of 24and 7that is height and radius respectively)
=√625
=25cm
area of sheet required = csa of cone
=πrl
=22/7×7×25
=22×25
=550cm^2
this is the area of sheet for one cap
for 10 caps
550×10
=550cm^2
radius=7cm
therefore slant height( l ) =√h^2+r^2
= √576+49 ( square of 24and 7that is height and radius respectively)
=√625
=25cm
area of sheet required = csa of cone
=πrl
=22/7×7×25
=22×25
=550cm^2
this is the area of sheet for one cap
for 10 caps
550×10
=550cm^2
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