Question

A joker’s cap is in the form of a right circular cone of base radius 7 cm and its slant height is 20 cm. The area of the sheet required to make 10 such caps is
4400
440
2200
880

Answer 1

Slant Height of the joker's cap = 20cm ( given ).

The Base Radius of the cap = 7cm ( given ).

As we assume π = 22

7

The Curved Surface Area of the Right Circular Cone is = π × r × l or πrl.

Curved Surface Area = 22/7 × 7 × 20.

Curved Surface Area = 22 × 20 = 440 cm²

We obtained Curved Surface Area of 1 cap = 440 cm².

Now,

The area of sheet required to make 10 caps.

= Curved Surface Area of 1 cap × 10

= 440 cm² × 10

= 4400 cm²

4400 cm² sheet is required for making such 10 caps..

Hope it helps..

Thank You..

Answer 2

$\huge\mathfrak\green{Answer:}$

Given:

• We have been given that a joker’s cap is in the form of a right circular cone of base radius 7 cm and its slant height is 20 cm.

To Find:

• We need to find the area of the sheet required to make 10 such caps.

Solution:

We have been given that the slant height of cone is 20cm and the radius of its base is 7cm.

Now, inoder to find the area of sheet, we first need to find the curved surface area of the cone.

We know that the curved surface area of the cone is πrl.

So, substituting the values we have, CSA of cone=

$\sf{ \dfrac{22}{7} \times 7 \times 20}$

$\sf{ = 440 {cm}^{2}}$

Therefore, the area of sheet required to make 1 cap is 440cm².

Now, the area of sheet required to make 10 such caps = 440 × 10 = 4400cm².

Hence, option A is correct.