A joker's cap is in the form of a right circular cone of base radius 7 cm
and height 24 cm. Find the area of the sheet required to make 10 such
caps.
Answers
Answer:
Step-by-step explanation:
radius = 7cm
height = 24 cm
l =√r² +h²
l =√7² + 24²
l = √49 + 576
l = √625
l = 25
Curved surface area of one conical cap =
πrl= (22/7)×(7)×25
= 550 cm ²
Curved surface area of 10 conical caps = 10 × 550 cm ²= 5500 cm²
∴ the area of sheet required to make 10 conical caps is 5500 cm²
A Joker's cap is in the form of the right circular cone.
The measure of the base radius of the cone is 7 cm.
The measure of slant height (L) of the cone is 25 cm.
To Find:
What is the area of the sheet required for 10 caps?
Solution: First, we need to find the area of 1 such cap that is in form of a circular cone.
As we know that
The curved Surface area of cone = πrl
Here,
r = 7 cm , l = 25 cm
implies{\rm } πrl
implies{\rm } ( 22/7 \times 7 \times 25 ) cm²
implies{\rm } ( 22 \times 25 ) cm²
implies{\rm } 550 cm²
So, The sheet required for one cap is 550 cm².
∴ Sheet required for making 10 caps
= 10 \times 550
= 5500 cm².
Hence, the sheet required for making 10 such caps will be 5500 cm².