A joker's cap is in the form of a right circular cone of base radius 7 cm and height
24 cm. Find the area of the sheet required to make 10 such caps.
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Answer
Given
r=7 cm
h=24 m
Let slant height be
′
l
′
We know
l
2
=h
2
+r
2
l
2
=24
2
+7
2
l
2
=576+49
l
2
=625
l=25 cm
Curved surface area of 1 jokers cap =πrl
=
7
22
×7×25
=22×25
=550 cm
2
So,
Curved surface area of 10 jokers cap =10×550
=5500 cm
2
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