Question

A joker's cap is in the form of a right circular cone of base radius 7 cm and height
24 cm. Find the area of the sheet required to make 10 such caps.
​

Answer 1

Answer:

Answer

Given

r=7 cm

h=24 m

Let slant height be

′

l

′

We know

l

2

=h

2

+r

2

l

2

=24

2

+7

2

l

2

=576+49

l

2

=625

l=25 cm

Curved surface area of 1 jokers cap =πrl

=

7

22

×7×25

=22×25

=550 cm

2

So,

Curved surface area of 10 jokers cap =10×550

=5500 cm

2