Question

A joker's cap is in the form of a right circular cone of base radius 7cm and height 24 cm find the area of the sheet required to make 10 such caps
​

Answer 1

Answer:

here is your solution ..

Answer 2

$radius \: = 7cm \\ height \: = 24cm$

$I = \sqrt{ {r}^{2} } + {h}^{2} \\ I = \sqrt{ {7}^{2} } + {24}^{2} \\ I = \sqrt{49} + 576 \\ I = \sqrt{625} \\ I =25$

Curved surface area of one conical cap =${\pi}rl = ( \frac{22}{7} ) \times (7) \times 25 \\ = {550 \: cm}^{2}$

Curved surface area of 10 conical cap =$10 \times {550 \: cm}^{2} \\ = {5500 \: cm}^{2}$

The area of sheet required to make 10 conica caps is ${5500 \: cm}^{2}$