A joker’s cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps
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Answers
Answer:
Given
r=7 cm
h=24 m
Let slant height be
′
l
′
We know
l
2
=h
2
+r
2
l
2
=24
2
+7
2
l
2
=576+49
l
2
=625
l=25 cm
Curved surface area of 1 jokers cap =πrl
=
7
22
×7×25
=22×25
=550 cm
2
So,
Curved surface area of 10 jokers cap =10×550
=5500 cm
2
Step-by-step explanation:
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Radius, r = 7 cm Height, h = 24 cm
Slant height,
l = √r² + h²
= √(7)² + (24)²
= √49 + 576
= √625
= 25 cm
Area of the sheet required to make each cap = πrl
= 22/7 × 7 cm × 25 cm
= 550 cm²
Area of the sheet required to make 10 such caps = 10 × 550 cm2 = 5500 cm2
Thus, the area of the sheet required to make 10 such caps is 5500 cm2.
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