Math, asked by Kabuto, 1 year ago

A joker's cap is in the form of a right circular cone of base radius 7cm and height 27cm.find the area of the sheet required to make 10 such caps

Answers

Answered by smartyshahid
3
area of the sheet is573.7cm and area of sheet is required to make 10 such Caps is 573.7*10=5737cm

chakradhar2002: can u expalin breifly
Answered by sethrollins13
10

✯✯ QUESTION ✯✯

A joker's cap is in the form of a right circular cone of base radius 7cm and height 27cm.find the area of the sheet required to make 10 such caps..

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✰✰ ANSWER ✰✰

\longmapsto\tt{Radius=7cm}

\longmapsto\tt{Height=27cm}

Firstly we will find the slant height : -

\longmapsto\tt{{l}^{2}=\sqrt{{h}^{2}+{r}^{2}}}

\longmapsto\tt{l=\sqrt{{(24)}^{2}+{(7)}^{2}}}

\longmapsto\tt{l=\sqrt{576+49}}

\longmapsto\tt{l=\sqrt{625}}

\red\longmapsto\:\large\underline{\boxed{\bf\green{l}\orange{=}\purple{25}}}

So , The slant height (l) is 25 cm...

Now ,

Using Formula : -

\longmapsto\tt{\small{\boxed{\bold{\bold{\green{\sf{C.S.A\:of\:Cone=\pi{rl}}}}}}}}

Putting Values : -

\longmapsto\tt{\dfrac{22}{\cancel{7}}\times{7}\times{\cancel{25}}}

\longmapsto\tt{22\times{25}}

\longmapsto\tt\bold{550{cm}^{2}}

\longmapsto\tt{Sheet\:Required\:for\:10\:caps=550\times{10}}

\longmapsto\tt\boxed{5500{cm}^{2}}

So , Sheet required for 10 caps is 5500cm²...

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