Question

A joker's cap is in the form of a right circular cone of the base radius 7 cm and height 24 cm. Find the area of the sheet required to make 10 such caps.​

Answer 1

Answer:

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Answer 2

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{Given :}}}}}}}$

$\sf{r=7 c.m}$

$\sf{h=24 c.m}$

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{To\:Find}}}}}}}$

$\sf{Area \:of\: sheet \:required\: to\: make\: 10 \:such \:caps}$

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{Solution:}}}}}}}$

$\sf{Let \:slant \:height\: be , l}$

$\sf{We\: know\: that}$

$\sf{l^2= h^2+r^2}$

$\sf{l^2= 24^2+7^2}$

$\sf{l^2= 576 +49}$

$\sf{l^2 = 625}$

$\sf{l= 25\:c.m}$

$\sf{Curved\: surface\: area \:of \:1 \:jokers \:cap = πrl}$

$\sf{= \dfrac{22}{7} \times 7 \times 25}$

$\sf{=22×25}$

$\sf{=550 \:c.m^2}$

$\sf{So, }$

$\sf{Curved\: surface\: area\: of 10\: jokers \:cap}$ $\sf{=10×550}$

$\sf{=5500 \:c.m ^2}$

Answer 3

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{Given :}}}}}}}$

$\sf{r=7 c.m}$

$\sf{h=24 c.m}$

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{To\:Find}}}}}}}$

$\sf{Area \:of\: sheet \:required\: to\: make\: 10 \:such \:caps}$

$\large{\red{\underline{\underline{\textsf{\maltese\:{\red{Solution:}}}}}}}$

$\sf{Let \:slant \:height\: be , l}$

$\sf{We\: know\: that}$

$\sf{l^2= h^2+r^2}$

$\sf{l^2= 24^2+7^2}$

$\sf{l^2= 576 +49}$

$\sf{l^2 = 625}$

$\sf{l= 25\:c.m}$

$\sf{Curved\: surface\: area \:of \:1 \:jokers \:cap = πrl}$

$\sf{= \dfrac{22}{7} \times 7 \times 25}$

$\sf{=22×25}$

$\sf{=550 \:c.m^2}$

$\sf{So, }$

$\sf{Curved\: surface\: area\: of 10\: jokers \:cap}$ $\sf{=10×550}$

$\sf{=5500 \:c.m ^2}$