.A joker’s cap is in the form of cone of base radius 7cm and height 24 cm. Find the area of the sheet to make 10 such caps. write simple answer please .
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Given :
- A joker’s cap is in the form of cone of base radius 7cm and height 24 cm.
To Find :
- The area of the sheet to make 10 such caps = ?
Solution :
- Radius of cone = 7 cm
- Height of cone = 24 cm
First of all we need to find the Slant Height of the cone :
→ Slant Height = √(Radius)² + (Height)²
→ Slant Height = √(7)² + (24)²
→ Slant Height = √49 + 576
→ Slant Height = √625
→ Slant Height = 25 cm
- Hence,the slant height of the cone is 25 cm.
Now,let's find the lateral surface area of cone :
→ CSA of cone = πrl
→ CSA of cone = 22/7 × 7 × 25
→ CSA of cone = 22 × 25
→ CSA of cone = 550 cm²
- Hence,the area of the sheet to make 1 such caps is 550 cm².
Finding area of the sheet to make 10 such caps :
→ CSA of 10 cones = 10 × πrl
→ CSA of 10 cones = 10 × 550
→ CSA of 10 cones = 5500 cm²
- Hence,the area of the sheet to make 10 such caps is 5500 cm².
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ANSWER
Sheet required will be on the curved surface area.
Curved surface area of 1 joker cap = πrl
Given,
- Radius, r = 7 cm
- Height, h = 24 cm
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