Question

A joker’s cap is in the form of cone of base radius 7cm and height 24 cm. Find the area of the sheet to make 10 such caps​

Answer 1

Given

r=7 cm

h=24 m

Let slant height be"l"

We know

l²=h²+r²

l²=24²+7²

l²=576+49

l²=625

l=25 cm

Curved surface area of 1 jokers cap =πrl

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{22}{7} \times 7 \times 25 \\ = 22 \times 25 \\ = 550cm {}^{2}$

So,

Curved surface area of 10 jokers cap =10×550

=5500 cm²

Answer 2

Answer:

Given:-

• r=7 cm

• h=24 m

Let slant height be"l"

We know:-

l²=h²+r²

l²=24²+7²

l²=576+49

l²=625

l=25 cm

Curved surface area of 1 jokers cap =πrl

$\frac {22}{7}$×7×25

=22×25

=550cm

2

So,

Curved surface area of 10 jokers cap =10×550

=5500 cm²