a joker's cap is in the form of right circular cone whose base radius is 7cm and height is 24cm find the area of the sheet required to make 10such caps
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radius = 7cm
height = 24 cm
l =√r² +h²
l =√7² + 24²
l = √49 + 576
l = √625
l = 25
Curved surface area of one conical cap =
πrl= (22/7)×(7)×25
= 550 cm ²
Curved surface area of 10 conical caps = 10 × 550 cm ²= 5500 cm²
∴ the area of sheet required to make 10 conical caps is 5500 cm²
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