Question

A joker’s cap is in the form of right circular cone whose base radius is 7cm and height is 24

cm. Find the area of the sheet required to make 10 such caps.​

Answer 1

$\huge \underline \mathbb \red {ANSWER}$

Give that,

The base radius of the cone =7cm

The height of the cone =24cm

Slant height of the cone =

$l = \sqrt{ {h}^{2} + {r}^{2} }$

=

$\sqrt{ {24}^{2} + {7}^{2} } \\ = 576 + 49 \\ {l}^{2} = 625 \\ = > l = \sqrt{625} \\ = > = 25cm$

Lateral surface area of a cone =

$\pi {r}l$

$\frac{22}{7} \times 7 \times 25 \\ = 550cm {}^{2}$

Area of the sheet to make a 10 caps =

$10 \times \pi rl$

$10 \times 550 \\ = 5500cm {}^{2}$

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