Question

A joker's cap is in the form of right circular cone whose radius 7cm and height is 24 cm and find the area of the sheet required to make 10 such caps.

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Answer 1

Answer:

Summary: It is given that there is a joker's cap is in the form of a right circular cone of base radius 7 cm and height 24 cm. We have found that the area of the sheet required to make 10 such caps is 5500 cm2.

Answer 2

Answer:

Given  

r=7 cm

h=24 m

Let slant height be 'l'

 

We know

l^2 = h^2+r^2

l^2= 24^2+7^2

l^2  =576+49

l^2  =625

l=25 cm

Curved surface area of 1 jokers cap =πrl

                                                           = 22/7×7×25

                                                           =22×25

                                                           =550 cm^2

 

So,  

Curved surface area of 10 jokers cap =10×550

                                                              =5500 cm^2