A jokers cap is in the form a right circular cone of base radius 7 cm and height is 3:4 find the ratio of their volumes
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Radius(r) = 7 cm
Height (h)= 27 cm
Slant height(l) = √h² + r²
l = √27² + 7²
l = √729 + 49
l = √778
l = 27.89 cm
Now,
Curved surface area of a joker's cap = curved surface area of Cone = πrl
= (22/7) × 7× 27.89
Curved surface area of a joker's cap = 613.58 cm²
The sheet required to make 1 cap = 613.58 cm²
The sheet required to make 10 such caps = 613.58×10 = 6135.8 cm²
Hence, The sheet required to make 10 such caps is 6135.8 cm².
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Height (h)= 27 cm
Slant height(l) = √h² + r²
l = √27² + 7²
l = √729 + 49
l = √778
l = 27.89 cm
Now,
Curved surface area of a joker's cap = curved surface area of Cone = πrl
= (22/7) × 7× 27.89
Curved surface area of a joker's cap = 613.58 cm²
The sheet required to make 1 cap = 613.58 cm²
The sheet required to make 10 such caps = 613.58×10 = 6135.8 cm²
Hence, The sheet required to make 10 such caps is 6135.8 cm².
===============================
Read more on Brainly.in - https://brainly.in/question/1950871#readmore
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