Question

a jokers cap is in the form of a right circular cone of base radius 7cm and height 27cm. find the area of the sheet required to make 10 such caps.​

Answer 1

Answer:

Area of the sheet required to make 10 such caps=6138 cm²

Step-by-step explanation:

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Answer 2

${ \large{ \sf{ \underbrace{\underline{\bigstar \:Given\: :-}}}}}$

${ \bold{ \boxed{ \red{ \underline{ \bf \:Radius \:=\: 7cm }}}}}$

${ \bold{ \boxed{ \red{ \underline{ \bf \:height \:=\: 24 \:cm }}}}}$

${ \large{ \sf{ \underbrace{\underline{\bigstar \:Have\: to\: find \::-}}}}}$

area of the sheet required to make 10 such caps.

${ \large{ \sf{ \underbrace{\underline{\bigstar \:Lets\: do\: it :-}}}}}$

$\sf{l =√r² +h²}$

$\sf{l =√7² + 24²}$

$\sf{l = √49 + 576}$

$\sf{l = √625}$

$\sf{l = 25}$

$\small\color{skyblue}{Curved\: surface \:area\: of \:one \:conical \:cap}$

$\sf{= πrl= (22/7)×(7)×25}$

$\boxed{\sf\color{red}{= \:550\: cm ²}}$

$\small\color{skyblue}{Curved\: surface\: area\: \:of \:10\: conical \:caps}$

$\sf{= 10 × 550 cm ²}$

$\boxed{\sf\color{red}{= \:5500\: cm ²}}$

$\bold\color{green}{∴ the\: area\: of\: sheet \:required \:to\: make\: 10 \:conical\: caps\: is\: 5500 \:cm²}$

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