A jokers cap is in the form of a right circular cone of base radiu r=7cmand h=24cm. find the area of required to make 10 such cap
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l=√h2+r2
=√24×24+7×7
=√576+49
=√625
=25m
curved surface area=πrl
=22÷7×25
=550m
=1 cap= 550m
=10cap= 550×10
=5500m
=√24×24+7×7
=√576+49
=√625
=25m
curved surface area=πrl
=22÷7×25
=550m
=1 cap= 550m
=10cap= 550×10
=5500m
Rohanreddy:
answer absolutely correct
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