Question

A jokers cap is in the form of a right circular cone of base radius 7 cm and height 24 cm.Find the area of the sheet required to make 10 such caps.

Answer 1

Answer:

$\sf\: 5500\:cm^2$

Step-by-step explanation:

Given :-

• Radius of cone(r) = 7 cm
• Height of cone (h) = 24 cm.

To find :-

• The area of sheet required to make 10 such caps

Solution :-

$\rule{300}{1.5}$

Surface area of cone is = πrl

slant height(l) = $\sf\sqrt{h^2 + r^2}$

$\sf{\implies}\: l = \sqrt{24^2 + 7^2}$

$\sf{\implies}\: l = \sqrt{576 + 49}$

$\sf{\implies}\:l = \sqrt{625}$

$\sf{\implies}\: l = 25\:cm$

$\rule{300}{1.5}$

Surface area of jokers cap = $\sf\dfrac{22}{7}\times 7\times 25$

⇒ Surface area of joker’s cap = $\sf\: 550 cm^2$

∴ the area of the sheet required to make 10 such caps

$\sf{\implies}\: 550 \times 10 cm^2$

$\sf{\implies}\: 5500\: cm^2$

Answer 2

$\huge\mathfrak\pink{Answer!! }$

⟹5500cm

$\mathfrak\pink{Step-by-step explanation: }$

Radius = 7 cm

Height = 24 cm

The area of sheet

$\mathfrak\pink{Surface..area.. of.. cone..is = πrl \\}$

$\sf{\implies}\:</p><p>l = \sqrt{576 + 49}\\</p><p>⟹l= 576+49 \sf{\implies}\:</p><p>l = \sqrt{625}\\</p><p>⟹l= 625\sf{\implies}\: </p><p>l = 25\:cm \\</p><p>⟹l=25cm h 2 +r 2$

⇒l=550 cm^2550cm 2

Hence, the area of the sheet needed to make 10 more caps

⟹550×10cm 2

⟹5500cm

$\huge\mathfrak\pink{Hope..it..helps!! }$