Question

A journey of 192 km between two cities takes 2 hour less by a fast train than a slow train. If the average speed of the slow train is 16km/hr less then

Answer 1

then what.... please complete the question its the answer

Answer 2

hello shreyansh here is ur ans

diatance is , d= 192km, and speed of slow train is 16km/h, and time t = ? ,then since we know that

v= s÷t

which implies
t = s÷v


t = 192÷ 16 = 12 hour , if the fast train takes less time i.e, 2 hr less than, then time taken by the fast train will be

12-2 = t = 10hr ,

speed of the fast train is given by

V fast = s ÷t

this implies

v= 192÷ 10= 19.2 km/h

so this implies ,

velocity and time taken by fast train to reach 192 km are 19.2 km/h and 10 hr respectively

so i hope it helps u

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