Math, asked by muhammadhashir24, 10 months ago

A jug contain 870 ml of lemonade. Kenny drank 3/5 of the lemonade. How many lemonade left in the jug.

Answers

Answered by sakinamufddal5253
3

870  \times  \frac{3}{5} \\ 154 \times 3 \\ 264

So 264 ml is your answer

mark as brainliest answer

Answered by GulabLachman
1

348 ml of lemonade is left in the jug.

It is given in the question that,

The jug contains 870 ml of lemonade.

Again, Kenny drank 3/5 th of the total lemonade present in the jug.

So, Kenny drank = (3/5)*870 ml

= 522 ml

Volume of lemonade left = Full capacity of lemonade - Capacity of lemonade drank

= (870 - 522) ml

= 348 ml

This is the required answer.

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