Physics, asked by man190199, 8 months ago

a juggler start throing ball with the speed of 40 m​

Answers

Answered by monuchahar2323
0

Answer:

plz write complete question

Answered by riyaenterprises012
0

Answer:

11th

Physics

Motion in a Straight Line

Problems on Equation of Motion

A juggler keeps on moving f...

PHYSICS

A juggler keeps on moving four balls in air throwing the balls after regular intervals. When one ball leaves his hand (speed =20ms

−1

), the position of other balls (height in metre) will be :

(Take g=10ms

−2

)

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ANSWER

Time taken by the small ball to return to the hands of the juggler is

g

2v

=

10

2×20

=4s. So, he is throwing the balls after 1s each. Let at some instant, he throws the ball number 4. Before 1s of throwing it, he throws ball 3. So, the height of ball 3 is

h=ut−

2

1

gt

2

h

3

=20×1−

2

1

(10)(1)

2

=15m

Before 2s, he throws ball 2. So, the height of ball 2 is

h

2

=20×2−

2

1

×10(2)

2

=20m

Before 3s, he throws ball 1. So, the height of ball 1 is

h

1

=20×3−

2

1

×10(3)

2

⇒h

1

=15m

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