Question

a juggler throws a ball vertically upwards and catches it after 6 seconds find the time at which the ball is 20 m below the topmost point

Answer 1

See it will require pen and paper for me to solve I'll guide you to the answer

The ball takes 6 seconds thus it means the topmost point is reached in 3 seconds thus the velocity will! Be 30 m/s

Substituting in equation = u2 + 2a S

We can get s.. After getting s

Just take initial velocity to be zero and apply second law of motion ur+1/2at^2 you will get the answer it will be more than 3 and less than 5