Question

A jumping board of a swimming pool is at a height of 20m . A boy jumps followed by a girl after 1second . The boy has intial velocity zero both of them hit the water together .What was the intial velocity with which girl jumped ? Find their velocity when they hit the water together​

Answer 1

Answer:

boy v 20m/sec

girl v 25m/ sec

Explanation:

first we calculate the time taken by boy to jump

h=ut+1/2gt^2

20= 0+1/2*10*t^2

t= 2sec

now velocity of boy by which it jump

v=u+gt

v= 0 +10*2

v= 20m/sec