A(k−9,k−13), B(k−5,m)C(k,k-4)are 3 collinear points . find the value of m in terms of k
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Answer:
m=k-9
slope of AB=slope of BC
m-k+13/k-5-k+9=k-4-m/k-k+5
m-k+13/4=k-4-m/5
4k-16-4m=5m-5k+65
9k-81=9m
m=k-9
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see above..................
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