Question

a का मान ज्ञात कीजिए यदि A(-3, -14) और B(, -5) के मध्य दूरी 9 इकाई है ।​

Answer 1

SOLUTION

TO DETERMINE

The value of a such that the distance between A(-3, -14) and B(a, -5) is 9 unit

EVALUATION

Here the given points are A(-3, -14) and B(a, -5)

Now the distance between the given points

= AB

$\sf{ = \sqrt{ {(a + 3)}^{2} + {( - 5 + 14)}^{2} } }$

So by the given condition

$\sf{ \sqrt{ {(a + 3)}^{2} + {( - 5 + 14)}^{2} } = 9 }$

$\sf{ \implies \: {(a + 3)}^{2} + {( 9)}^{2} = {(9)}^{2} }$

$\sf{ \implies \: {(a + 3)}^{2} = 0 }$

$\sf{ \implies \: (a + 3) = 0 }$

$\sf{ \implies \:a = - 3 }$

FINAL ANSWER

The required value of a = - 3

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Answer 2

SOLUTION

TO DETERMINE

The value of a such that the distance between A(-3, -14) and B(a, -5) is 9 unit

EVALUATION

Here the given points are A(-3, -14) and B(a, -5)

Now the distance between the given points

= AB

= √(a+3)² +(−5+14)²

So by the given condition

√(a + 3)² + ( - 5 + 14)² = 9

⟹(a+3)² +(9)² =(9)²

⟹(a+3)² =0

⟹(a+3)=0

⟹a= −3

FINAL ANSWER

The required value of a = - 3