Question

a का मान ज्ञात कीजिए यदि A( 3, - 14) और B(a, -5) के मध्य दूरी 9 इकाई है​

Answer 1

$\huge \fbox \blue{a = 3}$

Solving :

$\sqrt{ {(a - 3)}^{2} + {( - 5 - ( - 14))}^{2} } = 9 \\ \\ = > \sqrt{ {(a - 3)}^{2} + {( - 5 + 14)}^{2} } = 9$

दोनों और वर्ग करने पर :

${a}^{2} - 6a + 9 + {(9)}^{2} = {(9)}^{2} \\ \\ = > {a}^{2} - 6a + 9 + 81 = 81 \\ \\ = > {a}^{2} - 6a + 9 = 0 \\ \\ = > {a}^{2} - 3a - 3a + 9 = 0 \\ \\ = > a(a - 3) - 3(a - 3) = 0 \\ \\ = > (a - 3)(a - 3) = 0 \\ \\ = > {(a - 3)}^{2} = 0 \\ \\ = > a = 3$

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Hope it helps ☺

Fóllòw Më ❤