Question

a kangaroo can jump 2.5 m vertically. what must be initial velocity of the kangaroo? (explain)

Answer 1

Using third equation of motion,

v^2 = u^2 + 2as v is equal to zero

 since velocity at highest point = 0 0 = u^2 + 2 ( - 9.8 ) × 2.5 0 = u^2 - 49 u^2

= 49 u = √49 u = 7 m/sec

The initial velocity= 7 m/sec

Answer 2

Answer:

The initial velocity of the kangaroo must be 7 m/s.

Explanation:

a = 9.8 m/s²

s = 2.5 m

v = 0 m/s

v² = u² + 2as

=> (0)² = u² + 2 * (-9.8) * 2.5

=> 0 = u² - 5 * 9.8

=> 0 = u² - 49

=> u² = 0 + 49

=> u² = 49

=> u = 7 m/s

So,

The initial velocity of the kangaroo must be 7 m/s.

Here, negative sign of acceleration shows that it is in the opposite direction of the velocity.