Math, asked by shrirajpawar338, 1 month ago

A Kangaroo can jump 2.5 m vertically. What must be the initial velocity of the kangaroo?​

Answers

Answered by ThatThinker
3

\qquad \huge{\underline{\underline{\boxed{\sf{\purple{❥︎sᴏʟᴜᴛɪᴏɴ ࿐}}}}}}

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{ \underline{ \mathbb \red{G} \green{I} \mathbb\blue{V} \purple{E} \mathbb \orange{N} \pink{\:T} \mathbb \red{H} \green{A} \mathbb \blue{T} \purple{:}}}\:

\red{ \longmapsto\:} Acceleration (a) = 9.8 m/s^2

\red{ \longmapsto\:} Displacement (s) = 2.5 m

\red{ \longmapsto\:} Velocity (v) = 0

 \\

{\underline{ \mathbb \red{T} \green{O} \mathbb\blue{\:F} \purple{I} \mathbb \orange{N} \pink{D:}}}\:

\red{ \longmapsto\:} Initial Velocity

 \\

We know that,

\boxed{ {{ \pink{ {v}^{2}  =  {u}^{2} + 2as }}} }

\red{ \longmapsto\:} \red{ {0}^{2}  =  {u}^{2}  + 2 \: (9.8) \: (2.5)} (The negative sign is used as the acceleration is in the opposite direction of the Velocity)

\red{ \longmapsto\:} \red{ 0 =  {u}^{2}  - 49}

\red{ \longmapsto\:} \red{ {u}^{2}  = 49}

\red{ \longmapsto\:} \red{u = 7m/s}

{\bold{ \mathbb \green{Therefore,\:the\:initial\:velocity}}} { \mathbb \green{of\:the\:kangaroo\:must\:be}}  \purple{7m/s}

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