A kangaroo Can jump 2.5m vertically. What must be initial velocity of kangaroo.
Answers
Answered by
75
Using third equation of motion,
v^2 = u^2 + 2as
v is equal to zero since velocity at highest point = 0
0 = u^2 + 2 ( - 9.8 ) × 2.5
0 = u^2 - 49
u^2 = 49
u = √49
u = 7 m/sec
ANSWER = 7 m/sec
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MARK AS BRAINLIEST
v^2 = u^2 + 2as
v is equal to zero since velocity at highest point = 0
0 = u^2 + 2 ( - 9.8 ) × 2.5
0 = u^2 - 49
u^2 = 49
u = √49
u = 7 m/sec
ANSWER = 7 m/sec
HOPE IT HELPS :):):):):)
MARK AS BRAINLIEST
nkishor34:
In above questions How you took acceleration = -9. 8
Because of gravity
Answered by
19
Answer:given
S=2.5m,
g=a=9.8m/sec square,u=?
,v=0
Explanation:
V2=u2+2as
02=u2+2*9.8*2.5
U2=2*9.8*2.5
U2=49
U=7m ......(taking square root on both side.
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