Question

A kangaroo Can jump 2.5m vertically. What must be the initial velocity of kangaroo.

Answer 1

v square = u square + 2as ( third eq of motion)
v is zero at highest point

0 = u square + 2 ( -9.8 ) × 2.5
0 = u square - 49
u square = √49
u = 7 m/sec

ANSWER = 7 m/sec


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Answer 2

Explanation:

given :

a = 9.8m/S2

s = 2.5

V=0

u =?

formula used

!

V2 =u2+2as

(0)2 = u2 + 2× (-9.8 ) (2.5)

Negative Sign is used as the acceleration in the direction opposite to that of velocity

0= u2 -49

u2= 49

u =7m/s

HOPE YOU UNDERSTAND