Question

A kangaroo jumps 1.28m vertically. What would be the initial velocity of the kangaroo?

Answer 1

h:1.28m
v=0.
let initial be u
then.
${v}^{2} = {u}^{2} - 2gh$
if v is 0
u=√2gh. take g as 10. and substitute

Answer 2

v² = u²+2gh
0² = u²+2×-9.8×1.28
-u² = -9.8×2.56
u² = 9.8×2.56
u² = 24.988
u = √24.988
u = 4.99 = 5.0 m/s

Initial velocity of kangaroo is approximately 5 m/s.

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