A kennel has 120 dogs divided into groups. Each group should have the same number of dogs. How many prime number of groups are possible
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since, 120 is divisible by the prime number 2, 3and 5 only. so only there groups are possible.
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HEY FRIEND.
HERE IS YOUR ANSWER.
NUMBER OF DOGS KENNEL HAVE=120.
ATQ. THEY SHOULD BE DIVIDED INTO PRIME NUMBER OF GROUPS AND EACH GROUP SHOULD HAVE EQUAL NUMBER OF DOGS.
SO NUMBERS THAT CAN DIVIDE 120=1,2,3,4,5,6,8,9,10,12,15,20,24,30,40,60,120.
OUT OF THOSE, PRIME NUMBERS=2,3 AND 5.
THEREFORE,IT CAN BE DIVIDED IN 2,3AND 5 GROUPS.
SO THREE GROUPS WILL BE MADE.
HOPE IT HELPS YOU.
IF IT REALLY HELPS YOU SO YOU CAN THANKS ME BY MARKING MY ANSWER AS BRAINLIEST ANSWER PLEASE.
HERE IS YOUR ANSWER.
NUMBER OF DOGS KENNEL HAVE=120.
ATQ. THEY SHOULD BE DIVIDED INTO PRIME NUMBER OF GROUPS AND EACH GROUP SHOULD HAVE EQUAL NUMBER OF DOGS.
SO NUMBERS THAT CAN DIVIDE 120=1,2,3,4,5,6,8,9,10,12,15,20,24,30,40,60,120.
OUT OF THOSE, PRIME NUMBERS=2,3 AND 5.
THEREFORE,IT CAN BE DIVIDED IN 2,3AND 5 GROUPS.
SO THREE GROUPS WILL BE MADE.
HOPE IT HELPS YOU.
IF IT REALLY HELPS YOU SO YOU CAN THANKS ME BY MARKING MY ANSWER AS BRAINLIEST ANSWER PLEASE.
GRANDMESSI:
Please mark it as brainliest
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