Question

A kettle transfers 6000 J of energy electrically. 1500 J of this is wasted. What is the efficiency of this kettle?

Answer 1

Answer:

75%

Explanation:

Answer 2

Given,

The total amount of energy transferred by a kettle electrically = 6000 J

Amount of energy wasted = 1500 J

To find,

The efficiency of the kettle.

Solution,

We can simply solve this numerical problem by using the following process:

Mathematically,

Efficiency = (total amount of supplied energy used)/(total amount of supplied energy) × 100

Now,

The total amount of supplied energy used by the kettle

= total amount of supplied energy - the amount of energy wasted

= 6000J - 1500J

= 4500J

Now, according to the question;

The efficiency of the kettle

= (total amount of supplied energy used)/(total amount of supplied energy) × 100

= 4500J/6000J × 100

= 3/4 × 100 %

= 75%

Hence, the efficiency of the kettle is equal to 75%.