Math, asked by poojanarayanan22, 1 year ago

A king asks a learned man to visit his palace. The man says I will come any day next month. But give me gold in gms equal to the date on which I come. The king asks the jeweler to make rings of 1 to 31 gms. The jeweler was smart and makes only 5 rings. What are the weights of those rings?

Answers

Answered by katariasuman00
49
You must have heard about binary digits. Just by using powers of 2, any number can be represented. This is a problem of binary digit calculation. The jeweler knew binary digits could represent anything. So he made rings of weight of 1 g, 2 g, 4 g, 8 g and 16 g. And every number below 32 can be represented as the sum of the weights of these rings.

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rishilaugh: thank you so much
Sagittarius29: Amazing answer
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Answered by rishilaugh
33
Seems like the jeweller was more intelligent than king and that's why he made 5 rings and helped king save on some budget! :D 

The Jeweller was knew Binary Counting  and with 5 digits it seems like all the 31 days can be counted
as  2^{5} =32

so jeweller will make rings of 1 gram ,2 gram , 4 gram , 8 gram ,and 16 gram
all the day can be achieved using this 
For if the learned man comes on 30th
king can give 16 gram, 8 gram ,4 gram and 2 gram ring
I hope it helps!

duragpalsingh: wow
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