A kit is flying at a height of 75 metres from the ground level, attached to a string inclined at 60 to the horizontal. Find the length of the string to the nearest metre.
Answers
Answer:
The length of the string is 50√3 m.
Step-by-step explanation:
GIVEN :
The height of a kite from the ground, AB = 10 m
Distance between the foot of the ladder and wall , BC = 2 m
String inclined at , ∠BCA (θ) = 60°
Let AC be the length of the string (h).
In right angle triangle, ∆ABC ,
sin θ = P/ H
sin 60° = AB/AC
√3/2 = 75/h
√3h = 75 × 2
h = 150/√3
h = (150 × √3)/(√3 × √3)
[By Rationalising ]
h = 150√3/ 3
h = 50√3
AC = 50√3 m
Hence , the length of the string is 50√3 m.
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Answer:
Length of the string is 87 m .
Explanation :
Let AC be the string of length, 'h' m and C be the point, makes an angle of 60° and the kite is flying at the height of 75 m from the ground level.
In ΔABC,
Given that : height of kite is AB = 75 m and angle C = 60°
Now, we have to find the length of the string.
So, we use trigonometric ratios.
In a triangle ABC
=> sinC = AB/AC
=> sin60° = 75/h
=> sin60°= 75/h
=> √3/2 = 75/h
=> √3/2 = 75/h
=> h = 150/√3 = 150/1.73
Therefore, h = 86.6 ≈ 87 m
Hence, length of string is 87 meters
