Question

a kite in the shape of a rhombus has diagonals 10cm and 24cm finds its area

Answer 1

$\sf{\huge{\underline{\purple{Given :-}}}}$

• A kite in the shape of a rhombus has diagonals 10cm and 24cm.

$\sf{\huge{\underline{\pink{To\:Find :-}}}}$

• The area of Kite.

$\sf{\huge{\underline{\green{Solution :-}}}}$

Let ABCD be a rhombus kite ,

• AC = 10 cm

• BD = 24 cm

Area of Rhombus,

AO = $\dfrac{1}{2}$ × AC × BD

➝ AO = $\dfrac{1}{2}$ × 10 × 24

➝ AO = $\dfrac{1}{2}$ × 240

➝ AO = 120 cm²

So, The The area of Kite is 120 cm².

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Answer 2

Step-by-step explanation:

Given :-

• Diagonal 1 = 10 cm
• Diagonal 2 = 24 cm

Find :-

• Area of rhombus = ?

We know that

Area of rhombus = ½ × ${d}_{1} \: {×} \: {d}_{2}$

Area of rhombus = ½ × 10 × 24

Area of rhombus = 5 × 24

Area of rhombus = 120 cm²