Question

a kite in the shape of a square with a diagonal 32cm and an isosceles triangle of base 8cm and side 6cm each is to be made if three different shades.how much paper of each shade has been used in it​

Answer 1

${\large\blue{\mathbb\fcolorbox{aqua}{darkblue}{\star \: QUESTION:}}}$

❥︎ Find:-

(i) 5/4+(-11/4)

(ii) (-6/13)-(-7/15)

(iii) (1/8)÷(3/4)

(iv) (3/11)×(2/5).

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${\large\blue{\mathbb\fcolorbox{aqua}{darkblue}{\star \: ANSWER:}}}$

❥︎ Solutions:-

$\begin{lgathered}(i) \: \frac{5}{4} + ( - \frac{11}{4} ) \\ \\ = \frac{5}{4} - \frac{11}{4} \\ \\ = \frac{5 - 11}{4} \\ \\ = \frac{ - 6}{4} \\ \\ = {\fbox { \frac{ - 3}{2}}}\end{lgathered}$

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$\begin{lgathered}(ii)\: (- \frac{6}{13}) - ( - \frac{7}{15} ) \\ \\ =( - \frac{6}{13} )+ ( \frac{7}{15} ) \\ \\ = - \frac{(6)(15)}{(13)(15)} + \frac{(7)(13)}{(15)(13)} \: [ Taking \: L.C.M.] \\ \\ = - \frac{90}{195} + \frac{91}{195} \\ \\ = \frac{-90+91}{195} \\ \\ = {\fbox { \frac{1 }{195 }}}\end{lgathered}$

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$\begin{lgathered}(iii) \: \frac{1}{8} ÷ \frac{3}{4} \\ \\ = \frac{1}{8} × \frac{4}{3} \\ \\ = \frac{4}{4×2 × 3} \\ \\ = \frac{1}{2×3} \\ \\ = {\fbox { \frac{1}{6}}}\end{lgathered}$

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$\begin{lgathered}(iv) \: \frac{3}{11} × \frac{2}{5} \\ \\ = \frac{3×2}{11×5} \\ \\ = {\fbox { \frac{6}{55}}}\end{lgathered}$

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