Question

A kite is flying at a height of 50√3 m from the horizontal. It is attached with a string and makes an angle 60° with the horizontal. Find the length of the string.

Answer 1

LINE OF SIGHT: The line of sight is a line drawn from the eye of an observer to the point in the object viewed by the observer.

ANGLE OF ELEVATION: The angle of elevation of an object viewed is the angle formed by the line of sight with the horizontal , when it is above the horizontal level.

ANGLE OF DEPRESSION:The angle of depression of an object viewed is the angle formed by the line of sight with the horizontal , when it is below the horizontal level.

•Angle of elevation and depression are always acute angles.

•If the observer moves towards the perpendicular line(Tower/ building) then angle of elevation increases and if the observer move away from the perpendicular line(Tower/ building) angle of elevation decreases.

SOLUTION:
GIVEN:
BC = 50 m(the height of the kite)
∠BAC = 60°

Let AC=  x m be length of the String of the kite

In ∆ABC ,
sin 60° = BC / AC = P/ H
√3/2 = 50√3 / x
√3x = 50√3 × 2
x = (50√3 × 2)/√3
x= 50 × 2 = 100 m

AC = 100 m

Hence , the length of the String is 100 m.

HOPE THIS WILL HELP YOU...

Answer 2

Hey!!


Here is your answer,,

Height of kite from ground (AB) = 50√3m

Length of string attached with kite (AC) = x m

Angle of elevation = 60°


Sin 60° = P/h

√3/2 = AB/AC

√3/2 = 50√3/AC

AC = (50√3 × 2)/√3

AC = 50 × 2

AC = 100m

Length of the string is 100m


Hope it helps you...

Thanks..
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