Question

A kite is flying at a height of 60 m above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 60°. Find the length of the string, assuming that there is no slck in the string.​

Answer 1

Answer:

• Length of string = 40√3 cm.

Step-by-step explanation:

Draw a figure, based on given instruction,

[ Refer to the attachment ]

➡Let BC = Height of the kite from the ground, BC = 60 m

➡AC = Inclined length of the string from the ground and

➡A is the point where string of the kite is tied.

To Find: Length of the string from the ground i.e. the value of AC

From the above figure,

sin 60° = BC/AC

⇒ √3/2 = 60/AC

⇒ AC = 40√3 m

Thus, the length of the string from the ground is 40√3 m.

Answer 2

$\huge\mathfrak\red{Answer :) }$

AB represents the distance of a kite from ground.

⟹ ∴ AB = 60 m

⟹ seg AC represents the length of the string

$\tt { \fbox {\pink { m ∠ ACB = 60º }}}$

$\red{In\:right \:angled\: ∆ ABC,}$

⟹ sin 600 = side opposite to 600/Hypotenuse

⟹ ∴ sin 600 = AB/AC

⟹ ∴ √3/2 = 60/AC

⟹ ∴ AC = 120/√3

⟹ ∴ AC = (120/√3)× (√3/√3)

⟹ ∴ AC = 40√3 m

⟹ ∴ AC = 40 × 1.73

⟹ ∴ AC = 69.2

$\mathfrak\green{ Hope\:it\:help\: you}$

$\mathfrak\blue{ mark\:as\:brainlist\: please}$