Question

A kite is flying at a height of 75m above the ground an angle of 60° with ground. find the length of the string​

Answer 1

Step-by-step explanation:

Let the string DE be of the length x. The height of the kite CD is 75 m. It is given that the wire ED makes an angle of 60° with the horizontal. We will apply trigonometric formulas in triangle DCE as follows -

$\tt \: \: \: In \: \: Δ \: \: DCE,$

$\tt \: sin 60° = \frac{CD }{ ED}$

$\: \tt \: \: \: \: \frac{ \sqrt{3} }{2} = \frac{75}{x}$

$\tt \: \: \: \: \: \: \: x = 75 \times \frac{ \sqrt{3} }{2} = 64.95≈65m$

This is the length of the string to the nearest metre, which is the required answer.

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Note: In such types of questions, it is important to read the language of the question carefully and draw the diagram step by step correctly. When the diagram is drawn, we just have to apply basic trigonometry to find the required answer.

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Answer 2

Answer:

The answer is 50√3 m.

Step-by-step explanation:

Height of the kite= 75m

Angle made by the string and the kite= 60°

sin 60°= height of the kite/string of the kite

sin60°=75/string

√3/2=75/string

string=75×2/√3

string=50√3m

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