A kite is formed by adjoining two triangles of sides 20cm, 40cm and 40cm respectively. And third triangle is at the tail of sides 6cm, 6cm and 4cm. Find the total area of paper used in making this kite. ( Use √15 = 3.87 and √2 =1.41)
Answers
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Solution :-
Sides of adjoining two triangles is a = 20 cm , b = 40 cm and c = 40 cm .
so,
→ semi perimeter = s = a + b + c/2 = (20 + 40 + 40) / 2 = 50 cm .
then,
→ Area of both ∆'s = 2[√{s * (s - a) * (s - b) * (s - c)}] = 2[√(50 * 30 * 10 * 10) = 2*10*10√15 = 200 * 3.87 = 774 cm²
and,
→ semi perimeter of third ∆ = (6 + 6 + 4)/2 = 8 cm
so,
→ Area of third ∆ = √(8 * 2 * 2 * 4) = 2 * 2 * 2 * √2 = 8√2 = 8 * 1.41 = 11.28 cm² .
then,
→ Total area of paper used in making kite = 774 + 11.28 = 785.28 cm² (Ans.)
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