Question

A kite is made of special paper that costs 40p per cm. If BD = 6 cm, AO = 4 cm and CO = 8 cm, find the cost of making the kite.​

Answer 1

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₹14.40

Given :-

cost = 40 rupees /cm

BD = 6cm , AO = 4cm , CO = 8cm

To find :-

cost of making the kite

Solution :-

Area of kite :

= area of ∆ AOB + ∆ AOD + ∆ BOC + ∆ COD

= area of right angled triangle

$\frac{1}{2} \times l \times w$

so , using the given formula we can find the answer

let's put the values

$\\ = 2 (\frac{1}{2} \times 3 \times 4) + 2( \frac{1}{2} \times 3 \times 8) \\ \: \: \: \: \: \: \: \: \: \: \: (\because \: OA \: \: and \: \: O C \: are \: \\ \: \: \: \: \: \: \: \: perpendicular \: to \: BD) \\ = 2 + 24 \\ = 36 {cm}^{2}$

cost of paper needed will be 36cm²

cost of 36cm² paper :

$= 40 \times 36 \\ = 1440 \: paise \\ \\ \huge \red{= \: ₹ \: 14.40 \: }$

Hope it will be helpful

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