A kite PQRS, Where QS is 8cm, PS is 4.5cm and RS is 6cm
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In the process of construction of the kite, we use the property that a kite has two pairs of equal adjacent sides and unequal sides. We draw a line PQ of any reasonable length. We take any point on it. At L, construction RU ⊥ PQ is shown.
Along LR and LU, cut off LA = LY = 4 cm with A as centre, we draw an arc of radius 4 cm. With Y as centre, we draw another arc of radius 4 cm intersecting the previous arc at E. We join EA and EY. With A as centre and radius 6 cm, we draw an arc on the other side of RS. With Y as centre, we draw another arc of radius 6 cm intersecting the previous arc at S. Join AS and YS. Thus we obtain the required kite EASY.
Answered by @lBrainlyking001l
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