Question

A l + H2O gives rise to a l 2 O3 + H2O balancing

Answer 1

Answer:

Explanation:

Nice                                             hjkcx

Answer 2

Explanation:

Given:

To do:

Balance the given reaction

2Al+6H2O Give rise to 2Al(OH3)+3H2

Solution:

The given reaction is . For this reaction the number of atoms in the:

Reactant side

Al = 1

H = 2

O = 1

Product side

Al = 2

O = 3

H = 5

As the number of atoms in the reactant as well as product side is not equal, the given equation is not a balanced one.

To balance it certain changes must be made. The given equation with some alteration gives:

2Al+6H2O Give rise to 2Al(OH3)+3H2

When the number of atoms in the above reaction is calculated, it gives:

Reactant side:

Al = 2

H = 12

O = 6

Product side:

Al = 2

H = 12

O = 6

Thus both the reactants as well as product contains equal number of atoms, the above-given reaction is a balanced reaction.

Conclusion:

Unbalanced equation:  

Al+H2O give rise to Al(OH3) +H2

Balanced equation:

2Al+6H2O Give rise to 2Al(OH3)+3H2