a=l-m, b=m-n, c=n-l , then find the value of (x^a)^n (x^b)^l (x^c)^m
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(x^a)^n (x^b)^l (x^c)^m=
x^an x^bl x^cm=(x)^an+bl+cm
=(x)^nl-nm+ml-nl+nm-ml
=x^0=1
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